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8h^2+12h=4896
We move all terms to the left:
8h^2+12h-(4896)=0
a = 8; b = 12; c = -4896;
Δ = b2-4ac
Δ = 122-4·8·(-4896)
Δ = 156816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{156816}=396$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-396}{2*8}=\frac{-408}{16} =-25+1/2 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+396}{2*8}=\frac{384}{16} =24 $
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